If a copper ring is moved quickly towards the south pole of a powerful stationary bar magnet,then:

$A$ coil of $n$ turns and resistance $R \ \Omega$ is connected in series with a resistance $R/2$. The combination is moved for time $t$ seconds through a magnetic flux change from $\Phi_1$ to $\Phi_2$. The induced current in the circuit is:

$A$ flat circular coil has $100$ turns of wire of radius $10 \ cm$. $A$ uniform magnetic field exists in a direction perpendicular to the plane of the coil and it grows at a rate of $0.1 \ T \ s^{-1}$. The induced emf in the coil is:

The magnetic flux through a circuit of resistance $R$ changes by an amount $\Delta \phi$ in time $\Delta t$. Then the total quantity of electric charge $Q$ which is passing during this time through any point of the circuit is given by:

$A$ flexible wire loop in the shape of a circle has a radius that grows linearly with time. There is a magnetic field perpendicular to the plane of the loop that has a magnitude inversely proportional to the distance from the center of the loop,i.e.,$B(r) \propto \frac{1}{r}$. How does the emf $E$ vary with time?

Two circular coils $A$ and $B$ are facing each other as shown in the figure. The current $i$ through coil $A$ can be altered.